75 lines
1.9 KiB
Markdown
75 lines
1.9 KiB
Markdown
---
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title: 第一次作业（题目）
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date: 2020-10-30 09:47:21
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tags:
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---
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# 第一题
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写出下列程序运行的结果：
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```C
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#include <stdio.h>
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int main()
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{
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int a, b;
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char c1, c2;
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float d, e;
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double f, g;
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long m, n;
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unsigned int p, q;
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a = 61; b = 62;
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c1 = 'a'; c2 = 'b';
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d = 3.56; e = -6.78;
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f = 3157.890121; g = 0.123456789;
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m = 50000; n = -60000;
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p = 32768; q = 4000;
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printf("sizeof: %d, a = %d, b = %d\n", sizeof(int), a, b);
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printf("sizeof: %d, c1 = %c, c2 = %c\n", sizeof(char), c1, c2);
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printf("sizeof: %d, d = %-6.2f, e = %-6.2f\n", sizeof(float), d, e);
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printf("sizeof: %d, f = %-15.6f, g = %-15.12f\n", sizeof(double), f, g);
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printf("sizeof: %d, m = %ld, n = %ld\n", sizeof(long), m, n);
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printf("sizeof: %d, p = %u, q = %u\n", sizeof(unsigned), p, q);
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return 0;
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}
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```
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# 第二题
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写出下列程序的运行结果：
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```C
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#include <stdio.h>
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int main()
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{
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int i, j, m, n;
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i = 8; j = 10;
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m = ++i; n = j++;
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printf("%d, %d, %d, %d\n", i, j, m, n);
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return 0;
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}
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```
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# 第三题
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求下面算术表达式的值：
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| # | 表达式 | 变量的值 |
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| :---: | :------------------------------------- | :--------------------------------- |
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| 1 | `3.5 + 1 / 2 + 56 % 10` | |
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| 2 | `(a++ * 1 / 3)` | 设`a = 2` |
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| 3 | `x + a % 3 * (int)(x + y) % 2 / 4` | 设`x = 2.5, a = 7, y = 4.7` |
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| 4 | `(float)(a + b) / 2 + (int)x % (int)y` | 设a` = 2, b = 3, x = 3.5, y = 2.5` |
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| 5 | `x = (x = ++y, x + 5, x / 5)` | 设`x = 3, y = 4` |
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# 第五题
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写出下面表达式运算后`a`的值，设原来`a = 12`。
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1. `a += a`
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2. `a *= 2 + 3`
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3. `a /= a + a`
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4. `a += a -= a *= a`
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