47 lines
1.4 KiB
Markdown
47 lines
1.4 KiB
Markdown
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---
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title: 第一次作业（答案）
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date: 2020-10-30 09:53:13
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tags:
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---
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# 第一题
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写出下列程序运行的结果：
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```
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sizeof: 4, a = 61, b = 62
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sizeof: 1, c1 = a, c2 = b
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sizeof: 4, d = 3.56 , e = -6.78
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sizeof: 8, f = 3157.890121 , g = 0.123456789000
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sizeof: 4, m = 50000, n = -60000
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sizeof: 4, p = 32768, q = 4000
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```
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有些同学可能遇到警告：`"printf": 格式字符串"%d"需要类型"int"的参数，但可变参数 1 拥有了类型"size_t"`，这是因为`sizeof()`的类型是`size_t`而非`int`，在`printf()`中与`%d`的类型不匹配。可以尝试`%zu`（C99标准及以后）或`%lu`（ANSI C标准）。
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# 第二题
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```
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9, 11, 9, 10
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```
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# 第三题
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| # | 表达式 | 变量的值 | 结果 |
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| :---: | :------------------------------------- | :--------------------------------- | :---- |
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| 1 | `3.5 + 1 / 2 + 56 % 10` | | `9.5` |
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| 2 | `(a++ * 1 / 3)` | 设`a = 2` | `0` |
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| 3 | `x + a % 3 * (int)(x + y) % 2 / 4` | 设`x = 2.5, a = 7, y = 4.7` | `2.5` |
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| 4 | `(float)(a + b) / 2 + (int)x % (int)y` | 设a` = 2, b = 3, x = 3.5, y = 2.5` | `3.5` |
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| 5 | `x = (x = ++y, x + 5, x / 5)` | 设`x = 3, y = 4` | `1` |
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# 第五题
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写出下面表达式运算后a的值，设原来a = 12。
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1. `24`
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2. `60`
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3. `0`
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4. `0`
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